January 2022

ICSE Banking MCQS

10 th Maths ICSE Banking MCQS With Answers

10 Maths ICSE Banking MCQS With Answers

ICSE Banking MCQS

TS 10th class maths concept (E/M)

ICSE Banking MCQS

1. Mr Gupta gets ₹ 6,455 at the end of the one year at the rate of 14% per annum in a recurring deposit account  find the monthly instalment

A) ₹ 200

B) ₹ 600 

C) ₹  500

D) ₹ 300

 

2. Rahul deposited ₹ 500 every month in a recurring deposit account for 2 years. If the bank pays interest at the rate of 7% per annum, then the amount he gets on maturity is

A) ₹ 7865

B) ₹ 12875

C) ₹875

D) ₹13865

3.  Meena opens a recurring deposit account in a bank and deposits ₹ 600  for 20 months, find the maturity value of this account if the bank pays interest at the rate of 10% per annum

A) ₹ 78650

B) ₹ 2350

C) ₹12350

D) ₹13050

 
 

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Real Numbers Feature Image

TS 10th Real Numbers Previous Question Papers – Solutions

Real Numbers

 

one mark1. Insert 4 rational numbers between 1 and Real Numbers one mark questions 1 without using formula Real Numbers one mark questions 2

 Sol: we have to insert 4 rational numbers between 1 and Real Numbers one mark questions 1 and 1

4 +1 = 5

1 can be written as  Real Numbers one mark questions 3

Lcm of (4, 5) = 20

2. The prime factorisation of a natural number (n) is 23 × 32 × 52 × 7. How many consecutive zeros will it have at the end of it? Justify your answer.

Sol:

 n = 23 × 32 × 52 × 7

    = 2 × 22 × 32 × 52 × 7

    = 2 × 32 × 7 (52 × 22)

    = 2 × 32 × 7 × (10)2 = 12600

∴ n has 2 consecutive zeros at the end

3. Find the value of Real Numbers one mark questions 5

Sol:

Real Numbers one mark questions 6

4. Write any two irrational numbers between 3 and 4

Sol: 

 Real Numbers one mark questions 8

 5. Find the value of 	Find the value of log_√2⁡256

	Find the value of log_√2⁡256 

 6.  Find the HCF and LCM of 90, 144 by using the prime factorisation method

Sol:

Real Numbers one mark questions 18

7.  Is Real Numbers one mark questions 16 rational or irrational?  justify your answer

Sol:

Real Numbers one mark questions 17

8. Expand Real Numbers one mark questions 19

Sol:

Real Numbers one mark questions 20

9. Find the HCF of 24 and 33 by using division method

Sol:

33 > 24

 33 = 24 × 1 + 9Real Numbers one mark questions 20

 24 = 9 × 2 + 6

  9 = 6 × 1 + 3

  6 = 3 × 2 + 0

 

 

∴ HCF of 24 and 33 = 3

10. Find the value of Real Numbers one mark questions 22

Sol:

Real Numbers one mark questions 23

11. Ramu says, “if Real Numbers one mark questions 25 = 0, the value of x is 0”. Do you agree with him? Give reason.

Sol:

Real Numbers one mark questions 24

 

 

10 th maths concept Image

 

two marks1. Write any three numbers of two digits. Find the LCM and HCF for the above numbers by the prime factorisation method.

Sol: let 10, 12, 16 be three two-digit numbers

         Prime factarisation of 10 = 2 × 5 = 21× 51

         Prime factarisation of 12 = 2 × 2× 3 = 22 × 3

         Prime factarisation of 16 = 2 × 2× 2× 2 = 24

HCF of 10, 12 and 16 = 21 = 2

LCM of 10, 12 and 16 = 24 × 3× 5 = 8 × 3× 5 = 120

2. Give an example for each of the following

(i) The product of two irrational numbers is a rational number

(ii) The product of two irrational numbers is an irrational number

Sol:

Real Numbers one mark questions 26

3. State with reasons which of the following are rational numbers and which are irrational numbers

 Real Numbers one mark questions 27

4. Expand Real Numbers one mark questions 28

Real Numbers one mark questions 29


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Pair Of linear equations in two variables Feature Image

TS 10th Chapter 4 Pair of Linear Equations in Two Variables

TS 10th Chapter 4 Pair of Linear Equations in Two Variables

TS 10th Chapter 4 Pair of Linear Equations in Two Variables, Parallel, coincident, and intersecting lines. Dependent and independents lines

An equation of the form ax + by + c = 0 where a, b, c are real numbers and a2 + b2 ≠ 0 is called a linear equation in two variables x and y.

Two linear equations in the same variables are called a pair of linear equations in two variables

a1x + b1y + c1 = 0; a2x + b2y + c2 = 0 are the pair of linear equations in two variables in x and y.

Solution of Pair of linear equations in two variables:

For linear equations in two variables, there are infinitely many solutions.

Ex:  x + y = 10

x =7, y = 3; x = 6, y = 4; x = 1, y = 9; x =2, y = 8; x=3, y = 7 like we have infinitely   many solutions.

⇰ For finding exact values of x and y we have to know two linear equations.

⇰ A pair linear equations in two variables solved by four methods

  1. Graphical method
  2. Substitution method
  3. Elimination method
  4. Cross – Multiplication method

Solving the pair of linear equations in two variables by using graphical Method:

 1. 2x + y −5 = 0, 3x – 2y − 4 = 0

linear equations in two variables 1      linear equations in two variables 2

v

After plotting the points in the above tables in Cartesian plane, we observe that two straight lines intersect at the point (2, 1)

There is only one solution for this pair of linear equations in two variables.

These equations are known as consistent pair of linear equations and they have a unique solution.

2. 2x – 3y = 15; 4x – 6y = 9

linear equations in two variables 4    Linear equations in two variables 5

 

linear equations in two variables 6

After plotting the points in the above tables in Cartesian plane, we observe that two straight lines are parallel

There is no solution for this pair of linear equations in two variables.

These equations are known as inconsistent pair of linear equations and they have no solution.

3. 3x + 4y = 2; 6x + 8y = 4

linear equations in two variables 7 linear equations in two variables 8

linear equations in two variables 9

 

After plotting the points in the above tables in Cartesian plane, we observe that two straight lines are coincide

There are infinitely many solutions for this pair of linear equations in two variables.

These equations are known as consistent pair of linear equations and they have infinitely solution.

Consistent and inconsistent:

If the system of equations has a solution, then they are consistent. If the system of equations has no solution, then they are inconsistent.

The relationship between coefficients and the nature of the equation system:

linear equations in two variables 10

Examples:

1. Draw the graph of the following pair of linear equations in two variables and find their solution from the graph

    3x – 2y = 2 and 2x + y = 6

linear equations in two variables 11linear equations in two variables 12

linear equations in two variables 13

The two lines intersect at the point (2, 2)

∴ solutions is x = 2, y = 2

2. Draw the graph of the following pair of linear equations in two variables and find their solution from the graph

    x – 2y = –1 and 2x – y – 4 = 0

linear equations in two variables 14linear equations in two variables 15

linear equations in two variables 16

The two lines intersect at the point (3, 2)

∴ solutions is x = 3, y = 2

3. Represent the solution of linear equation graphically

     x – 2y = –3 and 2x + y = 4

linear equations in two variables 17linear equations in two variables 18

linear equations in two variables 19

The two lines intersect at the point (1, 2)

∴ solutions is x = 1, y = 2

Word problems:

1. Neha went to a sale to purchase some points and skirts. When her friend asked her how many of each she had bought, she answered “The number of skirts is two less than twice the number of points purchased. Also, the number of number of skirts is four less than four times the number of pants purchased”.

Help her friend to find how many pants and skirts Neha bought.

Sol:

Let the number of points = x

and the number of skirts = y

the number of skirts is two less than twice the number points purchased

⟹ y = 2x – 2

the number of number of skirts is four less than four times the number of pants purchased

⟹ y = 4x – 4

linear equations in two variables 20linear equations in two variables 21

linear equations in two variables 22

The two lines intersect at the point (1, 0)

∴ solution is x = 1, y = 2

No. of Points = 1 and no. of skirts = 0

2. 10 students of a class X took part in a Mathematics quiz. If the no. of girls is 4 more than the no. of boys, then find the no, of boys and no. of girls who took part in the quiz.

Sol:

let the no. of boys = x

No. of girls = y

Total no. of students = 10

⟹ x + y = 10

The no. of girls is 4 more than the no. of boys

⟹ y = x + 4

⟹ x – y = – 4

linear equations in two variables 23 linear equations in two variables 24 linear equations in two variables 25

The two lines intersect at the point (3, 7)

∴ solution is x = 3, y = 7

No. of boys = 3 and no. of girls = 7

3. Half the perimeter of a rectangular garden, whose length is 4m more than its width is 36 m. Find the dimensions of the garden.

Sol:

let the width of garden = x m.

Length of garden = y m.

Length of garden is 4m mote than its width

⟹ y = x + 4

x – y = – 4

half of the perimeter of rectangular garden is 36 m.

⟹ x + y = 36

⟹ x – y = – 4

linear equations in two variables 26 linear equations in two variables 27 linear equations in two variables 28

The two lines intersect at the point (16, 20)

∴ solution is x = 16, y = 20

Width of garden = 16 m and Length of garden = 20 m

4. The area of a rectangle gets reduced by 80 sq units if its length is reduced by 5 units and breadth is increased by 2 units. If we increase the length by 10 units and decrease the breadth by 5 units, the area will be increased by 50 sq units. Find the length and breadth of rectangle.

Sol:

Let the length of rectangle = x units

the breadth of rectangle = y units

The area of rectangle = xy sq units

If the Length of rectangle is reduced by 5 units and breadth is increased by 2 units, then area will be reduced by 80 sq units.

⟹ (x – 5) (y + 2) = xy – 80

⟹ xy + 2x – 5y – 10 = xy – 80

⟹ 2x – 5y = – 70

If length is increased by 10 and breadth decreased by 5 then area will be increased by 50 squnits

⟹ (x + 10) (y – 5) = xy + 50

⟹ xy – 5x + 10y – 50 = xy + 50

⟹ – 5x + 10y = 100

linear equations in two variables 29 linear equations in two variables 30 linear equations in two variables 31

The two lines intersect at the point (40, 30)

∴ solution is x = 40, y = 30

Length of rectangle = 40 units and Breadth of rectangle = 30 units

5. In X class, if three students sit on each bench one student will be left, if four students sit on each bench, one bench will be left. Find the number of students and number of benches in that class.

Sol:

Let the no. of students = x

The no. of benches = y

If three students sit on each bench one student will be left

⟹ 3y = x – 1

⟹ x – 3y = 1

If four students sit on each bench one bench will be left

⟹ 4 (y – 1) = x ⟹ 4y – 4 = x

⟹ x – 4y = – 4

linear equations in two variables 32 linear equations in two variables 33 linear equations in two variables 34

The two lines intersect at the point (16, 5)

∴ solution is x = 16, y = 5

No. of students = 16 and No. of benches = 5

The relationship between coefficients and the nature of the equation system Related Problems:

1. Check whether the following pair of linear equations have a unique solution, infinitely many solutions or no solution

(i) 2x + 3y = 1; 3x – y = 7

(ii) 2x + 3y = 5; 4x + 6y = 10

(iii) 5x + 3y = 4;10x + 6y = 12

Sol:

(i) Given equations are x + 3y = 1; 3x – y = 7

a1 = 1, b1 = 3, c1 = 1; a2 = 3, b2 = –1, c2 = 7

linear equations in two variables 35

∴ Given equations have unique solution

(ii) Given equations are      2x + 3y = 5; 4x + 6y = 10

a1 =2, b1 = 3, c1 = 5; a2 = 4, b2 = 6, c2 = 10

linear equations in two variables 37

∴ Given equations have infinite solutions

(iii) Given equations are 5x + 3y = 4;10x + 6y = 12

a1 =5, b1 = 3, c1 = 4; a2 = 10, b2 = 6, c2 = 12

linear equations in two variables 36

∴ Given equations have no solution

2. For what value of ‘p’ the following pair of equations has a unique solution

      2x + py = – 5 and 3x + 3y = – 6

Sol:

Given equations are 2x + py = – 5, 3x + 3y = – 6

a1 =2, b1 = p, c1 = –5; a2 = 3, b2 = 3, c2 = –6

Above equations have a unique solution

linear equations in two variables 38

∴ Given pair of linear equations have a unique solution when p ≠ 2

3. For what value of ‘p’ the following pair of equations has a unique solution

      px + 3y –(p – 3)= 0 and 12x + py – p = 0

Sol:

Given equations are px + 3y – (p – 3) = 0, 12x + py – p = 0

a1 =p, b1 = 3, c1 = – (p – 3),; a2 =12, b2 = p, c2 = –p

Above equations have infinitely many solution

linear equations in two variables 39

∴ Given pair of linear equations have infinitely many solutions when p = ±6

4. For what value of ‘k’ the following pair of equations represent coincident lines.

   3x + 4y + 2 = 0 and 9x + 12y + k = 0

Sol:

Given equations are 3x + 4y + 2 = 0 and 9x + 12y + k = 0

a1 =3, b1 = 4, c1 = 2; a2 = 9, b2 = 12, c2 = k

Above equations are coincident lines

linear equations in two variables 40

∴ Given pair of linear equations are coincident when k = 6

5. For what value of ‘k’ the following pair of equations represents the parallel lines

        2x – ky + 3 = 0 and 4x + 6y – 5 = 0

Sol:

Given equations are 2x – ky + 3 = 0, 4x + 6y – 5 = 0

a1 =2, b1 = –k, c1 = 3; a2 = 4, b2 = 6, c2 = –5

Above equations represents parallel lines

linear equations in two variables 41

∴ Given pair of linear equations represents parallel lines when k = – 3

Substitution Method:

In this method, we make one of the variables x or y as the subject from the 1st equation (or 2nd equation). Substitute this equation in 2nd equation (or 1st equation) and get the value of the variable involved, then by substituting this value in any one of the equations we get the value of second variable.

 

1. Solve the following pair of equations by using substitution method

    2x – y = 5 and 3x + 2y = 11

Sol:

Given equations are 2x – y = 5 ———— (1)

3x + 2y = 11———– (2)

From (1)

y = 2x – 5

substitute y value in (2)

⟹ 3x + 2(2x – 5) = 11

3x + 4x – 10 = 11

7x = 11 + 10 = 21

x = 3

now y = 2x – 5

⟹ y = 2(3) – 5 = 6 – 5 = 1

∴ the solution is x = 3 and y = 1

 

2. Solve the following pair of equations by using substitution method

     2x + 3y = 9 and 3x + 4y = 5

Sol:

Given equations are 2x + 3y = 9 ———— (1)

3x + 4y = 5———– (2)

From (1)

3y = 9 – 2x

linear equations in two variables 44

∴ the solution is x = – 21 and y = 17

 

3. Solve the following pair of equations by using substitution method

    3x – 5y = – 1 and x – y = – 1

Sol:

Given equations are 3x – 5y = – 1 ———— (1)

x – y = – 1———– (2)

From (2)

y = x + 1

substitute y value in (1)

⟹ 3x – 5(x + 1) = – 1

3x – 5x – 5= – 1

– 2x – 5= – 1

– 2x = – 1 + 5

– 2x = 4 ⟹ x = – 2

now y = x + 1

⟹ y = – 2 + 1 = – 1

∴ the solution is x = – 2 and y = – 1

4. Solve the following pair of equations by using substitution method

     x +  = 6 and 3x –   = 5

Sol:

linear equations in two variables 45

5. Solve the following pair of equations by using substitution method

      0.2x + 0.3y = 1.3 and 0.4x + 0.5y = 2.3

Sol:

linear equations in two variables 46

linear equations in two variables 47

Elimination Method:

In this method first we eliminate one of the two variables by equating its coefficients. This give a single equation which can be solved to get the value of the other variable

Steps for Elimination Method:

  • Write the both the equations in the form of ax + by = c
  • Multiply both the equations by suitable non-zero real number to make the coefficient of one variable (x or y) equal
  • If the variable to be eliminated has the same sign in both the equations, subtract one equation from another to get an equation in one variable.
  • Solve the equation for the one variable
  • Substitute the value of this variable in any one of the given equations and find the value of the eliminated variable.

1. Solve the following pair of equations by using Elimination method

     2x – y = 5 and 3x + 2y = 11

linear equations in two variables 48

2. Solve the following pair of equations by using the Elimination method

     8x + 5y = 9 and 3x + 2y = 4

linear equations in two variables 49

3. Solve the following pair of equations by using the Elimination method

     3x + 4y = 25 and 5x – 6y = –9

linear equations in two variables 50

4. Solve the following pair of equations by using the Elimination method

     2x + y = 5 and 3x – 2y = 4

linear equations in two variables 51

5. Solve the following pair of equations by using Elimination method

     3x + 2y = 11 and 2x + 4y =4

linear equations in two variables 52

 


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