The Plane (2m Questions & Solutions) || V.S.A.Q’S||

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This note is designed by the ‘Basics in Maths’ team. These notes to do help the intermediate First-year Maths students.
Inter Maths – 1B two mark questions and solutions are very useful in IPE examinations.
These notes cover all the topics covered in the intermediate First-year Maths syllabus and include plenty of solutions to help you solve all the major types of Math problems asked in the IPE examinations.  


Question 1

Find the equation of the plane if the foot of the perpendicular from the origin to the plane is (2, 3, – 5).

Sol:

The plane passes through A and perpendicular to OA, then the line segment OA is normal to the plane.

  Dr’s of OA = (2, 3, – 5)

  The equation of the plane passing through point (x1, y1, z1) and dr’s (a, b, c) is

   a(x – x1) + b (y – y1) + c (z – z1) = 0

  ⟹ 2(x – 2) + 3 (y – 3) – 5 (z + 5) = 0

        2x – 4 + 3y – 9 – 5z – 25 = 0

        2x + 3y – 5z – 38 = 0

Question 2

Find the equation of the plane passing through the points (0, – 1, – 1), (4, 5, 1) and (3, 9, 4)

Sol:

The equation of the plane passing through the points (x1, y1, z1) (x2, y2, z2) (x3, y3, z3) isPlane 1

The plane passing through the points (0, – 1, – 1), (4, 5, 1) and (3, 9, 4) is

Plane 2   =0

Plane 3  = 0

   x (30 – 20) – (y + 1) (20 – 6) + (z + 1) (40 – 18) = 0

   x (10) – (y + 1) (14) + (z + 1) (22) = 0

  10x – 14y – 14 + 22z + 22 = 0

  10x – 14y + 22z + 8 = 0

  2(5x – 7y + 11z + 4) = 0

 ∴ the equation of the plane is 5x – 7y + 11z + 4 = 0

Question 3

Find the equation to the plane parallel to the ZX-plane and passing through (0, 4, 4).

Sol:

Equation of ZX-plane is y = 0

 Equation of the plane parallel to ZX-plane is y = k

 But it is passing through (0, 4, 4)

 ⟹ y = 4

Question 4

Find the equation to the plane passing through the point (α, β, γ) and parallel to the plane axe + by + cz + d = 0.

Sol:

The equation of the plane parallel to the plane ax + by + cz + d = 0 is ax + by + cz + k = 0

        But it is passing through the point (α, β, γ)

        a α + b β + c γ + k = 0

  ⟹ k = – a α – b β – c γ

   The equation of the plane is ax + by + cz – a α – b β – c γ = 0

    ⟹ a(x – α) + b (y – β)+ c (z – γ) = 0


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